When you roll up the body it slows down withacceleration g? 9,8 m / s ?, due to the gravitational pull of the Earth. That is why a certain time lobed body stops and starts moving in the opposite direction, downwards.

The distance from the point of changing the direction of motion of the body to the surface of the Earth and will be equal to the maximum lift height.

You will need

• - sekundomer-
• - kalkulyator-
• - Protractor.

instructions

1

Find the maximum height of lifting the body, thrownup with a stopwatch. It does not matter whether the body is thrown vertically or at an angle to the horizon. Using a stopwatch, note the time that the body was in flight. Measure the time in seconds. Because half the time, the body is held in the air rises, falls into the second half, divide the resulting value by 2.

2

Calculate the maximum height of the lifting body N. For this purpose, lift divided by 2 t flight time squared. The resulting value multiply by the gravitational acceleration g? 9,8 m / s ?, and divide the result by the number 2, H = g? T? / 2. The height get in meters.

3

Example. After throwing on the surface of the Earth body again fell on her through 4, at which the maximum height it rose? Take the time to lift the body to the maximum height. It is equal to half the total travel time 4/2 = 2. Substitute the value in the formula H = g? T? / 2 = 9.8? 2? / 2? 20 m. If you do not want greater accuracy, the value of the gravitational acceleration can be taken 10 m / s ?.

4

Determine the maximum height of lifting the body, ifIt is known for its initial velocity. It can be measured by special radar. In some devices, it was originally known. In that case, if the body is running vertically to the initial velocity v0, to find the maximum height of the lifting body that divide the square of the initial velocity by twice the value of acceleration of gravity, H = v0? / 2? G. Rate must be measured in meters per second.

5

Find the maximum height of the body lift,the initial velocity v0 which is directed at an angle to the horizontal. In the calculation, note that the body of the rise corresponds to only the vertical component of the velocity, which is equal to v0y = v0? Sin (?), Where? - Angle to the horizon, under which the body began its movement, its measure protractor. Then, to calculate the maximum height of lifting the body, you can use the formula described in the previous paragraph, and multiply the result obtained by the sine? Built in H = (v0? / 2? G) square? Sin? (?).